1，js代码 验证密码强度

如何用js代码对密码强度评分，根据得分显示密码强度呢？本文为大家提供一个验证密码强度的例子。
function checkpass(pass){ var username = document.getElementById('username').value; var score = testpass(pass.value,username); var password_label = document.getElementById('password_label'); if(score == -4) { password_label.innerHTML = '太短'; }else if(score == -2){ password_label.innerHTML = '与用户名相同'; }else{ var color = score < 34 ? '#edabab' : (score < 68 ? '#ede3ab' : '#d3edab'); var text = score < 34 ? '弱' : (score < 68 ? '一般' : '很好'); var width = score + '%'; password_label.innerHTML = "<span>"+text+"</span>"; } } </script> 请输入用户名：<br> <input type="text" class="inpt" name="username" style="width:160px" id="username" /><br> 请输入密码：<br> <input type="password" class="inpt" style="width:160px" onkeyup="javascript:checkpass(this)" name="pass" id="pass" /><br> <span id="password_label" style="width:160px;border:1px solid #F0F0F0"></span>

function testpass(password,username){ var score = 0; if (password.length < 4 ) { return -4; } if (typeof(username) != 'undefined' && password.toLowerCase() == username.toLowerCase()){return -2} score += password.length * 4; score += ( repeat(1,password).length - password.length ) * 1; score += ( repeat(2,password).length - password.length ) * 1; score += ( repeat(3,password).length - password.length ) * 1; score += ( repeat(4,password).length - password.length ) * 1; if (password.match(/(.*[0-9].*[0-9].*[0-9])/)){ score += 5;} if (password.match(/(.*[!,@,#,$,%,^,&,*,?,_,~].*[!,@,#,$,%,^,&,*,?,_,~])/)){ score += 5 ;} if (password.match(/([a-z].*[A-Z])|([A-Z].*[a-z])/)){ score += 10;} if (password.match(/([a-zA-Z])/) && password.match(/([0-9])/)){ score += 15;} if (password.match(/([!,@,#,$,%,^,&,*,?,_,~])/) && password.match(/([0-9])/)){ score += 15;} if (password.match(/([!,@,#,$,%,^,&,*,?,_,~])/) && password.match(/([a-zA-Z])/)){score += 15;} if (password.match(/^\w+$/) || password.match(/^\d+$/) ){ score -= 10;} if ( score < 0 ){score = 0;} if ( score > 100 ){ score = 100;} return score; function repeat(len,str){ var res = ""; for (var i = 0; i < str.length; i++ ){ var repeated = true; for (var j = 0, max = str.length - i - len; j < len && j < max; j++){ repeated = repeated && (str.charAt(j + i) == str.charAt(j + i + len)); } if (j < len) repeated = false; if (repeated) { i += len - 1; repeated = false; }else{ res += str.charAt(i); } } return res; } }

2，例子，使用以上的函数可对密码进行评分验证。